Five identical plates are arranged as shown in figure. Find the equivalent capacitance between point A and B, distance between each plate is d and area of each plate is A.
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Sol. First we will give number to each plate like
5 5', 1 1', 3 3', 4 4' are connected together so their potentials are same so 2 2' is at different potential. So now we can assume 5 5', 1 1', 3 3', 4 4' one point and 2 2' one point so
∴ equivalent capacitance is parallel combination of two capacitor = Leq = C + C = 2C
where 
∴ Leq = 
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